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Direct sum of groups : ウィキペディア英語版
Direct sum of groups

In mathematics, a group ''G'' is called the direct sum 〔Homology. Saunders MacLane. Springer, Berlin; Academic Press, New York, 1963.〕〔László Fuchs. Infinite Abelian Groups〕 of two subgroups ''H''''1'' and ''H''''2'' if
* each ''H''''1'' and ''H''''2'' are normal subgroups of ''G''
* the subgroups ''H''''1'' and ''H''''2'' have trivial intersection (i.e., having only the identity element e in common), and
* ''G'' = <''H''''1'', ''H''''2''>; in other words, ''G'' is generated by the subgroups ''H''''1'' and ''H''''2''.
More generally, ''G'' is called the direct sum of a finite set of subgroups if
* each ''H''''i'' is a normal subgroup of ''G''
* each ''H''''i'' has trivial intersection with the subgroup <>, and
* ''G'' = <>; in other words, ''G'' is generated by the subgroups .
If ''G'' is the direct sum of subgroups ''H'' and ''K'', then we write ''G'' = ''H'' + ''K''; if ''G'' is the direct sum of a set of subgroups , we often write ''G'' = ∑''H''''i''. Loosely speaking, a direct sum is isomorphic to a weak direct product of subgroups.
In abstract algebra, this method of construction can be generalized to direct sums of vector spaces, modules, and other structures; see the article direct sum of modules for more information.
This notation is commutative; so that in the case of the direct sum of two subgroups, ''G'' = ''H'' + ''K'' = ''K'' + ''H''. It is also associative in the sense that if ''G'' = ''H'' + ''K'', and ''K'' = ''L'' + ''M'', then ''G'' = ''H'' + (''L'' + ''M'') = ''H'' + ''L'' + ''M''.
A group which can be expressed as a direct sum of non-trivial subgroups is called ''decomposable''; otherwise it is called ''indecomposable''.
If ''G'' = ''H'' + ''K'', then it can be proven that:
* for all ''h'' in ''H'', ''k'' in ''K'', we have that ''h''
*''k'' = ''k''
*''h''
* for all ''g'' in ''G'', there exists unique ''h'' in ''H'', ''k'' in ''K'' such that ''g'' = ''h''
*''k''
* There is a cancellation of the sum in a quotient; so that (''H'' + ''K'')/''K'' is isomorphic to ''H''
The above assertions can be generalized to the case of ''G'' = ∑''H''''i'', where is a finite set of subgroups.
* if ''i'' ≠ ''j'', then for all ''h''''i'' in ''H''''i'', ''h''''j'' in ''H''''j'', we have that ''h''''i''
* ''h''''j'' = ''h''''j''
* ''h''''i''
* for each ''g'' in ''G'', there unique set of such that
:''g'' = ''h''1
*''h''2
* ...
* ''h''''i''
* ...
* ''h''''n''
* There is a cancellation of the sum in a quotient; so that ((∑''H''''i'') + ''K'')/''K'' is isomorphic to ∑''H''''i''
Note the similarity with the direct product, where each ''g'' can be expressed uniquely as
:''g'' = (''h''1,''h''2, ..., ''h''''i'', ..., ''h''''n'')
Since ''h''''i''
* ''h''''j'' = ''h''''j''
* ''h''''i'' for all ''i'' ≠ ''j'', it follows that multiplication of elements in a direct sum is isomorphic to multiplication of the corresponding elements in the direct product; thus for finite sets of subgroups, ∑''H''''i'' is isomorphic to the direct product ×.
==Direct summand==
Given a group G, we say that a subgroup H is a direct summand of G (or that splits form G) if and only if there exist another subgroup K\leq G such that G is the direct sum of the subgroups H and K
In abelian groups, if H is a divisible subgroup of G then H is a direct summand of G.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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